Quadratic equation

Solve for x:
x^2+25 x-54 = 0

The left hand side factors into a product with two terms:
(x-2) (x+27) = 0

Split into two equations:
x-2 = 0 or x+27 = 0

Add 2 to both sides:
x = 2 or x+27 = 0

Subtract 27 from both sides:
Answer: |  x = 2             or              x = -27

x^2+25x-54=0

 

A=1, B=25, C=-54

 

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)Therefore

 

x= [-25(+-)SQRT(25^2-4*1*(-54)] / (2*1)

 

x= [-25(+-)SQRT(625-4*(-54)] / 2

 

x= [-25(+-)SQRT(841) / 2

 

x= [-25(+-)29 / 2

 

Two outcomes: 

 

x₁= (-25+29) / 2

x₁= 2

 

x₂=(-25-29) / 2

x₂=-27

 

X= 2 and X=-27