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solve this quadratic equation n2-9n-10=0

 Jun 17, 2016
 #1
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n2-9n-10 = 0

n2-9n = 10

n(2-9) = 10

n = 10/(2-9) = 10/-7 = -1.429 (rounded to 3 decimal places)

 Jun 17, 2016
edited by Guest  Jun 17, 2016
edited by Guest  Jun 17, 2016
edited by Guest  Jun 17, 2016
edited by Guest  Jun 17, 2016
 #2
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+5

Solve for n:
n^2-9 n-10 = 0

 

The left hand side factors into a product with two terms:
(n-10) (n+1) = 0

 

Split into two equations:
n-10 = 0 or n+1 = 0

 

Add 10 to both sides:
n = 10 or n+1 = 0

 

Subtract 1 from both sides:
Answer: |  n = 10     or     n = -1

 Jun 17, 2016

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