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How many zeroes does f(x)=(x-c)squared+d have if d>0?
Set the whole thing to 0. i.e. f(x) = 0.
\(f(x) = 0 \\ (x-c)^2 + d = 0\\ (x-c)^2 = -d\)
It has no real solutions. Therefore it have no zeroes.