The quadratic x^2 + bx + 16 = 0 has a double root. Find all possible values of b.
+2668 For the equation to have a double root, the discriminant (\(b^2-4ac\)) must equal 0. Substituting what we know, we have: \(b^2-4 \times 16 = 0 \)
Now, we have to solve for b.
Can you take it from here?
