+0  
 
0
76
1
avatar

The quadratic x^2 + bx + 16 = 0 has a double root. Find all possible values of b.

 May 7, 2022
 #1
avatar+2437 
0

For the equation to have a double root, the discriminant (\(b^2-4ac\)) must equal 0. Substituting what we know, we have: \(b^2-4 \times 16 = 0 \)

 

Now, we have to solve for b. 

 

Can you take it from here?

 May 7, 2022

9 Online Users

avatar