The quadratic x^2 + bx + 16 = 0 has a double root. Find all possible values of b.

Guest May 7, 2022

#1**+1 **

For the equation to have a double root, the discriminant (\(b^2-4ac\)) must equal 0. Substituting what we know, we have: \(b^2-4 \times 16 = 0 \)

Now, we have to solve for b.

Can you take it from here?

BuilderBoi May 7, 2022