+0

# Question

#2
+2

$$-\frac{5}{6}=-0.8\overline3$$

$$\frac{2}{3}-\frac{3}{2}$$

Above, there is the original expession. To evaluate this, we must have common denominators. To do this, we must multiply the numerator and the denominator. If you multiply 3 by 2 and 2 by 3, then you will have a common denominator:

$$\frac{2}{3}*\frac{2}{2}=\frac{4}{6}$$

$$\frac{3}{2}*\frac{3}{3}=\frac{9}{6}$$

Notice how I am not actually changing the value of the fraction. I'm multiplying both fractions by 1, so I am not changing the value of the fraction, just the way the number is represented:

$$\frac{4}{6}-\frac{9}{6}=-\frac{5}{6}=-0.8\overline3$$

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May 23, 2017

#1
0

-5/6

May 23, 2017
edited by Guest  May 23, 2017
#2
+2

$$-\frac{5}{6}=-0.8\overline3$$

$$\frac{2}{3}-\frac{3}{2}$$

Above, there is the original expession. To evaluate this, we must have common denominators. To do this, we must multiply the numerator and the denominator. If you multiply 3 by 2 and 2 by 3, then you will have a common denominator:

$$\frac{2}{3}*\frac{2}{2}=\frac{4}{6}$$

$$\frac{3}{2}*\frac{3}{3}=\frac{9}{6}$$

Notice how I am not actually changing the value of the fraction. I'm multiplying both fractions by 1, so I am not changing the value of the fraction, just the way the number is represented:

$$\frac{4}{6}-\frac{9}{6}=-\frac{5}{6}=-0.8\overline3$$

TheXSquaredFactor May 23, 2017