\(\frac{(2x+10)^7}{(x+5)^6}\)
Since 2x + 10 can be factored as: 2(x + 5),
(2x + 10)7 = [ 2(x + 5) ]7 = 27(x + 5)7 = 128(x + 5)7
Therefore: (2x + 10)7 / (x + 5)6 = 128(x + 5)7 / (x + 5)6 = 128(x + 5)
