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What is the quadratic formula?

angelangelangel

 Dec 17, 2015

Best Answer 

 #2
avatar+1904 
+15

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

 

Everything SpawnofAngel says is right except that it is not y equals but x equals.

.
 Dec 17, 2015
edited by gibsonj338  Dec 17, 2015
 #1
avatar+2592 
+15

 

     -b + or - sqrt(b^2-4(a)(c))

 y= --------------------------------

                   2a

a= leading coeffiecent

b= second coeffiecent

c= last coeffiecent

such that y=ax2+bx+c

 Dec 17, 2015
 #2
avatar+1904 
+15
Best Answer

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

 

Everything SpawnofAngel says is right except that it is not y equals but x equals.

gibsonj338 Dec 17, 2015
edited by gibsonj338  Dec 17, 2015
 #3
avatar+118687 
+15

Also the equation being solved is 

ax^2+bx+c =0

 

 

NOT y=

 Dec 19, 2015

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