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Given that $f(x) = x^k$ where $k > 0$, what is the range of $f(x)$ on the interval $[1, \infty)$?

 Feb 5, 2021
 #1
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f(x) = x^k can take on all nonnegative real numbers so the range is [0,inf).

 Feb 6, 2021
 #2
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Guest answerer:

How would you get 0?

Melody  Feb 7, 2021

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