+0  
 
-1
53
2
avatar+194 

Given that $f(x) = x^k$ where $k > 0$, what is the range of $f(x)$ on the interval $[1, \infty)$?

 Feb 5, 2021
 #1
avatar
+1

f(x) = x^k can take on all nonnegative real numbers so the range is [0,inf).

 Feb 6, 2021
 #2
avatar+112513 
0

Guest answerer:

How would you get 0?

Melody  Feb 7, 2021

22 Online Users

avatar