+33665 For the general quadratic equation \(y=ax^2+bx+c\) the vertex occurs where \(x_{vertex}=-\frac{b}{2a}\)
To find the value of y at that point, put this back into the quadratic equation \(y_{vertex}=(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c\)
In vertex form the quadratic can now be written as \(y-y_{vertex}=(x-x_{vertex})^2\)
See if you can apply this to your particular quadratic equation.
+33665 For the general quadratic equation \(y=ax^2+bx+c\) the vertex occurs where \(x_{vertex}=-\frac{b}{2a}\)
To find the value of y at that point, put this back into the quadratic equation \(y_{vertex}=(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c\)
In vertex form the quadratic can now be written as \(y-y_{vertex}=(x-x_{vertex})^2\)
See if you can apply this to your particular quadratic equation.
