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(A); s= d/t (t)

and

(B): A=\pi r2 (r)

 Nov 6, 2015

Best Answer 

 #1
avatar+26400 
+25

(A); s= d/t (t)

and

(B): A=\pi r2 (r)

 

 

(A):

\(\begin{array}{rcll} s &=& \dfrac{d}{t} \qquad &| \qquad \cdot t \\ s\cdot t &=& d \qquad &| \qquad :s \\ t &=& \dfrac{d}{s} \\ \end{array}\)

 

(B):

\(\begin{array}{rcll} A &= &\pi r^2 \\ \pi r^2 &= & A \qquad &| \qquad :\pi \\ r^2 &= & \dfrac{A}{\pi} \qquad &| \qquad \sqrt{} \\ r &= & \sqrt{\dfrac{A}{\pi}} \\ \end{array}\)

 

 

laugh

 Nov 6, 2015
 #1
avatar+26400 
+25
Best Answer

(A); s= d/t (t)

and

(B): A=\pi r2 (r)

 

 

(A):

\(\begin{array}{rcll} s &=& \dfrac{d}{t} \qquad &| \qquad \cdot t \\ s\cdot t &=& d \qquad &| \qquad :s \\ t &=& \dfrac{d}{s} \\ \end{array}\)

 

(B):

\(\begin{array}{rcll} A &= &\pi r^2 \\ \pi r^2 &= & A \qquad &| \qquad :\pi \\ r^2 &= & \dfrac{A}{\pi} \qquad &| \qquad \sqrt{} \\ r &= & \sqrt{\dfrac{A}{\pi}} \\ \end{array}\)

 

 

laugh

heureka Nov 6, 2015

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