rectangle has area 30cm^2 and length sqrt(5). find its perimeter

A=30m²

l=\(\sqrt5\)m

w=?

P=?

 

A=lw

\(30=w\sqrt5\)

\({30\over\sqrt5}={30\sqrt5\over5}=6\sqrt5=w\)

P=2(l+w)

P=2(\(\sqrt5+6\sqrt5\))

=\(2*7\sqrt5=14\sqrt5\)

 

\(P=14\sqrt5\)