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Suppose the equation 5x²+x-3=0 has roots r and s. Find the value of r²-s².

 Jan 20, 2022
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 Find the value of r²-s².

 

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\(5x²+x-3=0\\ x^2+0.2x-0.6=0\\ x=-0.1\pm \sqrt{0.01+0.6}\\ r^2=0.463795\\ s^2=0.776205\\ \color{blue}r^2-s^2=-0.31241\)

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 Jan 20, 2022

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