To approach a runway, a plane must begin a 7° descent starting from a height of 5 miles above the ground. To the nearest mile, how many miles from the runway is the airplane at the start of this approach?
+1316 Hi CPhill
I think it should be this.
5miles/D = Tan(7°)
5/Tan(7°) = 40.72 or 41 miles
+129852 tan (7°) = h / 5 where h is the height....rearrange
h = 5 tan(7°) = about 0.614 mi = 1 mile [rounded to the nearest mile]
+1316 Hi CPhill
I think it should be this.
5miles/D = Tan(7°)
5/Tan(7°) = 40.72 or 41 miles
+118677 Dragonlance caught you napping on that one Chris. LOL
It is good to see you back on the forum Dragonlance. :)
+1316 Hi Melody
I been spending a lot of time studying for social science classes. I not want to flunk anything in my first year of school. I have a C now but I almost die to get it. I not complaining too much because I at least not almost die to get a D. hahaha
