Please find the next 4 terms in the following sequence and thanks:
1, 4, 9, 16, 25, 36, 49, 64, 81, 10, 22............?
After thinking about it for a few minutes, it suddenly hit me!!!!! I think it goes likes this:
"The sum of the digits of each term X number of term=the term!". So, we have:
1 X 1=1 first term, 2 X 2=4 second term, 3 X 3=9 third term..............
10th term=(1+0) X 10=10th term, 11th term=(1+1) X 11=22 , which is the 11th term, 12th term=(1+2) X 12=36, which is the 12th term, 13th term=(1+3) X 13=52, which is the 13th term, 14th term=(1+4) X 14=70............and so on.....90, 112, 136.............etc. So, the sequence is:
1, 4, 9, 16, 25, 36, 49, 64, 81, 10, 22, 36, 52, 70, 90, 112, 136...........etc.(I think!!!!!????).