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Evaluate the sum $\frac{1}{3^1} + \frac{2}{3^2} + \frac{3}{3^3} + \cdots + \frac{k}{3^k} + \cdots$

Guest Aug 6, 2020

Guest · Answer 1 · 2020-08-06T07:29:59

sumfor(k, 1, 1000, (k / (3^k)))= it converges to 3/4.