Solve for x in terms of y
5xy+3xy^2=7
\(5xy+3xy^2 = 7\\ x(5y+3y^2)=7\\ \text{we know that }5y+3y^2 \neq 0 \text{ as it's a factor of a non-zero number (7), so}\\ x = \dfrac{7}{5y+3y^2}\)
