simple algebra but im confused

Question

-1

694

1

+2864

Solve for x in terms of y

5xy+3xy^2=7

+6252

+1

Best Answer

$5xy+3xy^2 = 7\\ x(5y+3y^2)=7\\ \text{we know that }5y+3y^2 \neq 0 \text{ as it's a factor of a non-zero number (7), so}\\ x = \dfrac{7}{5y+3y^2}$

Rom Jan 19, 2019

Rom · Answer 1 · 2019-01-19T06:35:00

$5xy+3xy^2 = 7\\ x(5y+3y^2)=7\\ \text{we know that }5y+3y^2 \neq 0 \text{ as it's a factor of a non-zero number (7), so}\\ x = \dfrac{7}{5y+3y^2}$

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