+118723
Sin2(280°+2Π) x Log(Cos85°) + tanΠ2 - √567
Is this your question? If it is you can put it straight onto the home page calculator.
$$Sin^2(280+2\pi) \times log(Cos85) + tan2\pi - \sqrt{567}$$
Did you want it be discussed.
For starters
$$Sin^2(280+2\pi) =sin^2(280)$$
This is because the sine curve has a period of 2pi. After that it just repeats.
$$tan(2\pi)=0$$
+118723
Sin2(280°+2Π) x Log(Cos85°) + tanΠ2 - √567
Is this your question? If it is you can put it straight onto the home page calculator.
$$Sin^2(280+2\pi) \times log(Cos85) + tan2\pi - \sqrt{567}$$
Did you want it be discussed.
For starters
$$Sin^2(280+2\pi) =sin^2(280)$$
This is because the sine curve has a period of 2pi. After that it just repeats.
$$tan(2\pi)=0$$
