How do u find the y=my+b if you only know that the slope is o.5 and the xintercept is 28,0
+118654 How do u find the y=mx+b if you only know that the slope is o.5 and the xintercept is (28,0)
\(b=0.5\\ y=mx+0.5\\ sub \;\;in\;\; x=28\;\;and\;\; y=0\\ 0=m*28+0.5\\ m*28=-0.5\\ m=\frac{-0.5}{28}\\ m=\frac{-1}{56}\\~\\ y=\frac{-x}{56}+0.5 \)
+37084 I agree with Melody ....Mostly....
y = mx + b is the equation of a line with slope m and y-axis intercept b
you are given 'm' = 0.5 so your line equation becomes y = .5 x + b
you are given the 'x' axis intercept....(this is where y = 0) as 28, 0 so substitute this value into your equation to find 'b'
y = .5x + b
0 = .5 (28 ) + b
-14 = b
so your line equation becomes:
y = 0.5 x - 14
