\(f(s)=s^2-123s+75\)
Find \(f(0)\) from the equation above.
\(f(0)=0^2-123*0+75\)
\(f(0)=0-123*0+75\)
\(f(0)=0-0+75\)
\(f(0)=0+75\)
\(f(0)=75\)
That is what this web is for haleyππππππππππππ
We are just asking........what is the evaluation of the function when we substitute "0" in for "s" ????
Do you see what the answer is, Hayley????
\(f(s)=s^2-123s+75\)
Find \(f(0)\) from the equation above.
\(f(0)=0^2-123*0+75\)
\(f(0)=0-123*0+75\)
\(f(0)=0-0+75\)
\(f(0)=0+75\)
\(f(0)=75\)