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Solve by Substitution: 5x + 7y = 10 -3x + 14y = -6

 Jun 8, 2014

Best Answer 

 #1
avatar+3453 
+8

So we have to solve 5x + 7y = 10, -3x + 14y = -6 by substitution, and we do this by, you guessed it, substituting!

5x + 7y = 10   --We first have to get x = something, so we can substitute x to find y.

/5    /5    /5    --Divide everything by 5

x + 7/5y = 2

   -7/5y     -7/5y   --Subtract 7/5y from both sides

x = -7/5y + 2

 

-3x + 14y = -6

-3(-7/5y + 2) + 14y = -6      --Substitute x in

21/5y -6 + 14y = -6

         +6             +6

4 1/5y + 14y = 0

y = 0

 

5x + 7(0) = 10       --Now put in y to find x

5x = 10

x = 2

 

So y = 0 and x = 2.

 

Let's check it:

-3(2) + 14(0) = -6

-6 = -6  ✔

 Jun 8, 2014
 #1
avatar+3453 
+8
Best Answer

So we have to solve 5x + 7y = 10, -3x + 14y = -6 by substitution, and we do this by, you guessed it, substituting!

5x + 7y = 10   --We first have to get x = something, so we can substitute x to find y.

/5    /5    /5    --Divide everything by 5

x + 7/5y = 2

   -7/5y     -7/5y   --Subtract 7/5y from both sides

x = -7/5y + 2

 

-3x + 14y = -6

-3(-7/5y + 2) + 14y = -6      --Substitute x in

21/5y -6 + 14y = -6

         +6             +6

4 1/5y + 14y = 0

y = 0

 

5x + 7(0) = 10       --Now put in y to find x

5x = 10

x = 2

 

So y = 0 and x = 2.

 

Let's check it:

-3(2) + 14(0) = -6

-6 = -6  ✔

NinjaDevo Jun 8, 2014
 #2
avatar+128460 
+5

I like the way you add the "check' to your answers, NinjaDevo......it really brings it home that your solutions are correct......3 points from me!!!

 

 Jun 9, 2014
 #3
avatar+3453 
+5

Thanks CPhill.

 Jun 9, 2014

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