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solve each system using elimination or substitution: x+3y=13 -3x+2y=27

 Oct 15, 2014

Best Answer 

 #1
avatar+33661 
+5

x + 3y = 13     ...(1)

-3x + 2y = 27  ...(2)

 

Rearrange (1)  as  x = 13 - 3y  ...(3)

 

Put this into equation (2)

-3*(13 - 3y) + 2y = 27

-39 + 9y + 2y = 27

-39 + 11y = 27

 

Add 39 to both sides

11y = 66

 

Divide both sides by 11

y = 6

 

Put this into equation (3)

x = 13 - 3*6

x = -5

 

.

 Oct 15, 2014
 #1
avatar+33661 
+5
Best Answer

x + 3y = 13     ...(1)

-3x + 2y = 27  ...(2)

 

Rearrange (1)  as  x = 13 - 3y  ...(3)

 

Put this into equation (2)

-3*(13 - 3y) + 2y = 27

-39 + 9y + 2y = 27

-39 + 11y = 27

 

Add 39 to both sides

11y = 66

 

Divide both sides by 11

y = 6

 

Put this into equation (3)

x = 13 - 3*6

x = -5

 

.

Alan Oct 15, 2014

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