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avatar+1904 
  1. \((3+2x){}^{1/3}=0\)
  2. \(3+2{}^{x}=0\)
  3. \(\sqrt{-25}\times x=-10\)
  4. \((3x+2){}^{2}=0\)
 Jan 3, 2016
 #1
avatar+128475 
+5

1. (3 + 2x )^(1/3)  = 0         cube each side

 

3 + 2x  = 0^3

 

3 + 2x  =   0      subtract 3 from both sides

 

2x = -3              divide both sides by 3

 

x = -3/2

 

 

2.     3 + 2^x   = 0

 

This has no real solution.......an exponential like 2^x  is always positive and adding 3 to it still results in a positive......thus......the left side cannot = 0 in real terms

 

3.  sqrt(-25) * x = -10   

 

This has no real solution, either .....however .......we can find a complex one

 

5i * x = -10       divide both sides by 5i

 

x = -10/5i

 

x = -2/i       multiply top/bottom by i

 

x= -2i / -1

 

x = 2i

 

 

4. (3x + 2)^2  = 0        take the square root of both sides

 

3x + 2 = 0       subtract 2 from both sides

 

3x = -2      divide both sides by 3

 

x = -2/3

 

 

 

 

cool cool cool

 Jan 3, 2016

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