1. (3 + 2x )^(1/3) = 0 cube each side
3 + 2x = 0^3
3 + 2x = 0 subtract 3 from both sides
2x = -3 divide both sides by 3
x = -3/2
2. 3 + 2^x = 0
This has no real solution.......an exponential like 2^x is always positive and adding 3 to it still results in a positive......thus......the left side cannot = 0 in real terms
3. sqrt(-25) * x = -10
This has no real solution, either .....however .......we can find a complex one
5i * x = -10 divide both sides by 5i
x = -10/5i
x = -2/i multiply top/bottom by i
x= -2i / -1
x = 2i
4. (3x + 2)^2 = 0 take the square root of both sides
3x + 2 = 0 subtract 2 from both sides
3x = -2 divide both sides by 3
x = -2/3