$${\frac{{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}}{{\mathtt{3}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{x}}}{{\mathtt{2}}}}{\mathtt{\,-\,}}{\mathtt{3}} = {\frac{{\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{x}}}{{\mathtt{4}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}$$ (dont mind the extra x's) 2x/3 +x/2-3=3x/4+2