Loading [MathJax]/jax/output/SVG/jax.js
 
+0  
 
0
3627
1
avatar

Thank a lot , urgent

1.sinxcosx=3/2,for x=[0,pi]

 

2.cosxsinx=2,forx=[pi,pi]

3.sinx+3cosx=2,forx=[0,2,pi]

 Jan 26, 2016

Best Answer 

 #1
avatar+33654 
+10

Here's part 1:

 

sin - cos

 

Try a similar approach on parts 2 and 3.

 Jan 26, 2016
 #1
avatar+33654 
+10
Best Answer

Here's part 1:

 

sin - cos

 

Try a similar approach on parts 2 and 3.

Alan Jan 26, 2016

0 Online Users