sin^2(x) - 1 = 0
What is the sum (in degrees) of the angles x obtained?
sin^2 (x) - 1 = 0 factor as a difference of squares
(sin(x) + 1) (sin(x) - 1) = 0 set both factors to 0 and we have
sin(x) + 1 = 0 subtract 1 from both sides
sin(x) = -1 and this happens at 270°
For the other factor, we have
sin(x) - 1 = 0 add 1 to both sides
sin(x) = 1 and this happens at 90°
The sum of the solutions is 360°