Solve the system of linear equations using substitution.

 -3x + y = 3 and 3x + 2y = -12

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$\color{BrickRed} -3x + y = 3 \\ 3x-y=-3$

$3x + 2y = -12$

$3x=\color{blue}y-3=-2y-12$

$3y=-9$

$y=-3$

$-3x + y = 3\\ 3x=y-3\\ 3x=-3-3$

$x=-2$

  !