find where 2(x+3)-y=7 and 7x-3(y-1)=9 intersect on a graph. check your answer
+130536 2(x+3)-y=7 → 2x + 6 - y = 7 → y = 2x - 1 (1)
7x-3(y-1)=9 → 7x - 3y + 3 = 9 → 7x - 3y = 6 (2)
Substituting (1) into (2), we have
7x - 3[2x - 1] = 6 simplify
7x - 6x + 3 = 6
x + 3 = 6 subtract 3 from both sides
x = 3 and y = 2x -1 = 2(3) - 1 = 5
So (x,y) = (3, 5)
Here's a graph of the intersection of (1) and (2)........https://www.desmos.com/calculator/mcvtrkwpyj
