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# solve

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6x+c=k for x

A:x=  k- c/6

B. x=6 (k-c)

C.x=6(k+6)

D. x= k+c/ 6

Mar 1, 2019

#1
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A. Divide both sides by 6, and you get $$x +\frac c6 = \frac k6$$ . Subtract $$\frac c6$$ from both sides and you end up with $$x = \frac {k-c}{6}$$

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Mar 1, 2019

A. Divide both sides by 6, and you get $$x +\frac c6 = \frac k6$$ . Subtract $$\frac c6$$ from both sides and you end up with $$x = \frac {k-c}{6}$$