6x+c=k for x
A:x= k- c/6
B. x=6 (k-c)
C.x=6(k+6)
D. x= k+c/ 6
A. Divide both sides by 6, and you get \(x +\frac c6 = \frac k6\) . Subtract \(\frac c6\) from both sides and you end up with \(x = \frac {k-c}{6}\)
