someone tell me the formula?

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A 10 kg rock is suspended 320 m above the ground. Calculate the approximate speed with which the rock hits the ground

Guest Jan 9, 2016

+1832

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Best Answer

In addition to what Dragonlance say

the formula is \(v^2 = vi^2 + 2gd \)

where vi is the initial velocity and its zero because its start from rest

xvxvxv Jan 9, 2016

xvxvxv · Answer 1 · 2016-01-09T03:11:37

In addition to what Dragonlance say

the formula is \(v^2 = vi^2 + 2gd \)

where vi is the initial velocity and its zero because its start from rest

Dragonlance · Answer 2 · 2016-01-09T03:08:06

This is the formula.

\(v=\sqrt{2gd}\)

Earth's gravity is g (9.8m/s. Distance in meters is d. v is the speed in meters per second when it hit the ground.