+2354 Your question does not have an answer.
have a look at this;
$$\sqrt{p} = y$$
Now
if p=0 , y = 0
if p>0 , y >0
if p
Therefore if y
Hence, there exists no x for which $$\sqrt{x+6} = -8$$
There is a method involving non-real numbers which does solve your answer, but I don't assume you're a university student yet.
To make it more clear to you, let's say we work it out.
We square both sides (which is an operation where we need to check our answer)
$$x+6 = 64$$
$$x = 58$$
Now let's check the answer...
$$\sqrt{58+6} = \sqrt{64} = 8 \neq -8$$
And we find that there is no answer which suits our problem.
+2354 Your question does not have an answer.
have a look at this;
$$\sqrt{p} = y$$
Now
if p=0 , y = 0
if p>0 , y >0
if p
Therefore if y
Hence, there exists no x for which $$\sqrt{x+6} = -8$$
There is a method involving non-real numbers which does solve your answer, but I don't assume you're a university student yet.
To make it more clear to you, let's say we work it out.
We square both sides (which is an operation where we need to check our answer)
$$x+6 = 64$$
$$x = 58$$
Now let's check the answer...
$$\sqrt{58+6} = \sqrt{64} = 8 \neq -8$$
And we find that there is no answer which suits our problem.
