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Compute the value of 1+2+3+4+...+2019+2020+2021+2022.

 May 19, 2022
 #1
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1+2+3+4+...+2019+2020+2021+2022==S, solve for S

 

S ==[2022 x 2023] / 2 ==2,045,253

 May 19, 2022
 #2
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1      +      2   +  3+       4+.....2019+2020+2021+2022      flip it

2022+2021+2020+2019+......+    4+     3+      2+      1

add  it, which is then 2023 + 2023+ 2023+ 2023....., and there were 2022 of them in the first place, so multiply 2022 by 2023.

There are 2 sets of them, so divide by 2 because there was 1 in the question.

 May 19, 2022

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