Suppose ln x = 9, ln y = 3, and ln z = 27. Evaluate.
ln(xyz)
Since you have already given the ln of x, y, z as:9, 3, 27 that means that the ln(xyz)=9+3+27=39!!, because: x=e^9, y=e^3 and z=e^27.
The second part isn't clear the way you have written down.
