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Suppose r and s are the values of x that satisfy the equation x^2 - 2mx + (m^2 + 2m + 2) = 0
for some real number m. Find the minimum real value of r^2 + s^2.

 Nov 2, 2020
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The minimum value of r^2 + s^2 + is 8.

 Nov 2, 2020

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