How many solutions exist for the system of equations given below?
3a + 4b = 20 12a = 80 − 16b Select one: A. One solution B. Two solutions C. Infinitely many solutions D. No solutions
3a + 4b = 20
12a + 16b = 80
As you can see, if you multiply the first equation by 4, they are both the same.
This means there are no solutions (D) for this system of equations :)