+0  
 
0
75
1
avatar

Suppose a, b, c, and d are real numbers which satisfy the system of equations

a + 2b + 3c + 4d = 10

4a + b + 2c + 3d = 4

3a + 4b + c + 2d = -10

2a + 3b + 4c + d = −4.

Find a + b + c + d.

 May 5, 2022
 #1
avatar+2437 
+1

Add all the equations, then divide by 10.

 May 5, 2022
edited by BuilderBoi  May 5, 2022

4 Online Users