If a+b = 8, b+c = -3, and a+c = -5 +b, what is the value of the product abc?
My shot:
\(2a+2b+2c=b\)
\(a+b+c=\frac{b}{2}\)
\(-\frac{b}{2}=-5+b\)
\(-5=-\frac{3b}{2}\)
\(-10=3b\)
\(b=-\frac{10}{3}\)
\(a=\frac{34}{3}\)
\(c=-\frac{59}{3}\)
\(a\times b\times c=\frac{20060}{9}\)
huh, straight we got different answers......