So, another question.

But when I have a system of inequalities, which points do I count as part of the system and which points do I not. For example, if I had y>x^{2} and y<-2(x+2)^{2} +6 which points would be considered solutions

MrPatel
Apr 30, 2018

#1**+1 **

y > x^2

y < -2(x + 2)^2 + 6

Instead of inequalities, let's just set these equal and see if we can find the correct solutions

x^2 = -2(x + 2)^2 + 6

x^2 = -2(x^2 + 4x + 4) + 6

x^2 = -2x^2 -8x - 8 + 6

x^2 = - 2x^2 - 8x - 2 rearrange as

3x^2 + 8x + 2 = 0

Solving this with the Quadratic Formula, we get the solutions :

x = ( -4 - √10 ) / 3 ≈ -2.387

x = (-4 + √10 ) / 3 ≈ -0.279

We have three possible intervals for solutions

(-infinity, ≈ -2.87 ) U ( ≈-2.87, ≈ -0.279) U (≈ -0.279, infinity)

The way these usually work is that either the two outside intervals work or the middle interval does

Here's a graph to prove that the middle interval is correct :

https://www.desmos.com/calculator/uvqnynvqym

The solution area is where both graphs overlap

CPhill
May 1, 2018