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# tanø=3.62/4: ø=?

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tanø=3.62/4: ø=?

Guest Feb 28, 2017
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Guest Feb 28, 2017
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tanø=3.62/4: ø=?

A radius vector in a circle with r = 4 intersects the applied tangent

at height 3.62.

So

$$\ ∅ = 8$$

$$tan \ α = \frac{3.62}{4}$$

$$α = atan\ \frac{3.62}{4}=42°\ 8' \ 42''$$

!

asinus  Feb 28, 2017
edited by asinus  Feb 28, 2017

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