tanø=3.62/4: ø=?

42.1451

A radius vector in a circle with r = 4 intersects the applied tangent

at height 3.62.

So

\(\ ∅ = 8\)

\(tan \ α = \frac{3.62}{4}\)

\(α = atan\ \frac{3.62}{4}=42°\ 8' \ 42''\)

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