If f−1(g(x))=x3−1and g has an inverse, find g−1(f(7)).
f−1(g(x))=x3−1g(x)=f(x3−1)x=g−1(f(x3−1))7=23−1g−1(f(7))=g−1(f(23−1))=2
Thanks, Rom!
