If \(f^{-1}(g(x))=x^3-1\)and \(g\) has an inverse, find \(g^{-1}(f(7))\).
\(f^{-1}(g(x)) = x^3-1\\ g(x) = f(x^3-1)\\ x = g^{-1}(f(x^3-1))\\ 7 = 2^3-1\\ g^{-1}(f(7)) = g^{-1}(f(2^3-1)) = 2\)
Thanks, Rom!
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