The difference of a number squared and the number is one less than four times the number.

Let N be the number......so we have

N^2 - N  = 4N - 1      add 1 to both sides and subtract 4N from both sides

N^2 - 5N + 1  = 0  using the onsite calculator and substituting x for N, we have

$${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{\,-\,}}{\frac{\left({\sqrt{{\mathtt{21}}}}{\mathtt{\,-\,}}{\mathtt{5}}\right)}{{\mathtt{2}}}}\\
{\mathtt{x}} = {\frac{\left({\sqrt{{\mathtt{21}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{5}}\right)}{{\mathtt{2}}}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{0.208\: \!712\: \!152\: \!522\: \!08}}\\
{\mathtt{x}} = {\mathtt{4.791\: \!287\: \!847\: \!477\: \!92}}\\
\end{array} \right\}$$

Those are the two solutions......!!!!