(Since A is representing a digit, if A = 2 then A0 represents the integer 20.)
x^2 -wx - 10w = 0 (I chnged a to w for clarity)
Discriminant must be > 0
b^2 - 4ac > 0
w^2 -4(1)(-10w) >0
w^2 + 40w >0
w(w + 40) > 0 both w and (w+40) must be positive for this to be true
w >0 and w >-40 is restricted to w > 0 1 2 3 4 5 6 7 8 9 (since it must be positive single digit per Question)
Let 1A = 10 + A
Let A0 = 10A
So.....if we have integer solutions, the discriminant must be a perfect square
So
( 10+A)^2 - 4 (10A) =
100 + 20A + A^2 - 40A =
A^2 - 20A + 100 =
(A - 10) ( A -10) =
(A - 10)^2
This will be a perfect square for any integer A > 0
But since A must be a single digit....then....
A can be any positive integer from 1 - 9 inclusive