The perimeter of a rectangle is 46cm. What are the dimensions if the length is 4 less than twice the width?
we can give the width and length variables. lets call them x and y respectively. we know that y=2x-4
the perimeter is equal to 2x + 2y or 2(x + y).
the perimeter in terms of x is 2(x + 2x-4) = 2(3x-4) = 6x-8
if y=2x-4, then y=9*2 - 4=18-4=14.
the width is 9cm and the length is 14cm