The point (-9,-9) is on the terminal side of an angle t. Find csc(t) to 2 decimal places.

(-9, -9)  is in quadrant 3

And csc = r / y......so we need to fimd r....so

r  = sqrt [ (-9)^2 + (-9)^2 ]   =  9sqrt(2)

So .....  csc (t)   =  [9sqrt(2) ] / (-9)   =  -sqrt(2) ≈  -1.41