The price of gasoline fell by 10%. A few days later the price fell again (from the new lower price) by another 20%. If the price of gasoline is now $1.08, what was it orignally?
I came up with 1.4256 but that's not right apparently
If X is the originial price of gasoline:
X * 0.9 * 0.8 = 1.08 I.e the price decreases to 90% and then to 80% of that the new price, and becomes 1.08 $.
Divide both sides of the equation with (0.9*0.8) and you get:
X= 1.08/(0.9*0.8) --> X=1.5
If you prefer, you can begin with solving 0.9*0.8=0.72. So the originall equation would be X*0.72=1.08. Divide both sides with 0.72 and you get:
X=1.08/0.72= 1.5
Hope i helped!
If X is the originial price of gasoline:
X * 0.9 * 0.8 = 1.08 I.e the price decreases to 90% and then to 80% of that the new price, and becomes 1.08 $.
Divide both sides of the equation with (0.9*0.8) and you get:
X= 1.08/(0.9*0.8) --> X=1.5
If you prefer, you can begin with solving 0.9*0.8=0.72. So the originall equation would be X*0.72=1.08. Divide both sides with 0.72 and you get:
X=1.08/0.72= 1.5
Hope i helped!
Yes ? 
