+0  
 
+1
155
1
avatar+5 

The vertex of the right isosceles triangle is the center of the square. What is the area of the overlapping region?

[asy]
draw((-1,-1)--(1,-1)--(1,1)--(-1,1)--cycle);
draw(sqrt(3)*dir(30)--sqrt(3)*dir(-60)--(0,0)--cycle);
draw(.25*dir(30)--.25*(dir(30)+dir(-60))--.25*dir(-60));
label("10",(-1,0),W);

dot((0,0));
[/asy]

avasireddy094  Oct 7, 2018
 #1
avatar+94100 
0

If you want your question answered, especially if you want it answered quickly, it would be a good idea to present it properly.

Melody  Oct 8, 2018

16 Online Users

avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.