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The vertex of the right isosceles triangle is the center of the square. What is the area of the overlapping region?

[asy]
draw((-1,-1)--(1,-1)--(1,1)--(-1,1)--cycle);
draw(sqrt(3)*dir(30)--sqrt(3)*dir(-60)--(0,0)--cycle);
draw(.25*dir(30)--.25*(dir(30)+dir(-60))--.25*dir(-60));
label("10",(-1,0),W);

dot((0,0));
[/asy]

 Oct 7, 2018
 #1
avatar+102429 
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If you want your question answered, especially if you want it answered quickly, it would be a good idea to present it properly.

 Oct 8, 2018

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