The vertex of the right isosceles triangle is the center of the square. What is the area of the overlapping region?

[asy]

draw((-1,-1)--(1,-1)--(1,1)--(-1,1)--cycle);

draw(sqrt(3)*dir(30)--sqrt(3)*dir(-60)--(0,0)--cycle);

draw(.25*dir(30)--.25*(dir(30)+dir(-60))--.25*dir(-60));

label("10",(-1,0),W);

dot((0,0));

[/asy]

avasireddy094
Oct 7, 2018