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Find the smallest number θ larger than 16π such that sin⁡θ=\({ \sqrt2 \over 2}\).

 Nov 7, 2020
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      θ  = 16π + π/4    as sin(16π) is zero and √2/2 is the opposite/hypotenuse of a 45-45-90 triangle.

 Nov 7, 2020

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