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Three cards are dealt at random from a standard deck of 52 cards. What is the probability that the first card is a 4, the second card is a ACE , and the third card is a 2?

 Sep 7, 2018
 #1
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\(\left(\dfrac{1}{13}\right)\left(\dfrac{4}{51}\right)\left(\dfrac{4}{50}\right)= \dfrac{16}{33150} \approx 4.83\times10^{-4}\)

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 Sep 7, 2018
 #2
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I'd say... uhhh... a low probability!smiley

 Sep 7, 2018

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