Three cards are dealt at random from a standard deck of 52 cards. What is the probability that the first card is a 4, the second card is a ACE , and the third card is a 2?
\(\left(\dfrac{1}{13}\right)\left(\dfrac{4}{51}\right)\left(\dfrac{4}{50}\right)= \dfrac{16}{33150} \approx 4.83\times10^{-4}\)
I'd say... uhhh... a low probability!
+296 
