To approximate the straight line distance between point D and point E a woman walks 720ft from point D to point F then turns 47degrees to face point E and walks 940ft to point E. Find DE and the leanths of the angles of the triangle
+130540 We can use the Law of Cosines to find DE...so we have
DE^2 = 720^2 + 940^2 - 2(720)(940)cos47
DE^2 = 478847.0198200768
DE = about 692
And using the Law of Sines, we can find angle EDF
So we have
sin EDF / 940 = sin 47 / 692
sin EDF = 940sin47/692 = .9934573403495087
And using the sin inverse
sin-1 (.9934573403495087) = EDF= 83.44°
And the remaining angle, DEF = (180 - 47 - 83.44) = 49.56°
+130540 We can use the Law of Cosines to find DE...so we have
DE^2 = 720^2 + 940^2 - 2(720)(940)cos47
DE^2 = 478847.0198200768
DE = about 692
And using the Law of Sines, we can find angle EDF
So we have
sin EDF / 940 = sin 47 / 692
sin EDF = 940sin47/692 = .9934573403495087
And using the sin inverse
sin-1 (.9934573403495087) = EDF= 83.44°
And the remaining angle, DEF = (180 - 47 - 83.44) = 49.56°
