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Ranges from 6.57 to 7.93. Write the desired point ± tolerance statement. How do I do this?
 Feb 5, 2014
 #1
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AngelIshtar7:

Ranges from 6.57 to 7.93. Write the desired point ± tolerance statement. How do I do this?



I am really not sure what you need.

Maybe (7.93+6.57)/2 = 7.25 This is the centre of the range

then 7.93-7.25 = 0.68

So maybe it is
7.25±0.68

Does that look relevant to you? Nor sure. sorry.
I'll ask some of the others tonight
but you may wish to post in
http://mathhelpboards.com/potw/
or
http://mathhelpforum.com/
They both deal better with advanced questions.
 Feb 5, 2014
 #2
avatar+2353 
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AngelIshtar7:

Ranges from 6.57 to 7.93. Write the desired point ± tolerance statement. How do I do this?



Hi Angellshtar,

I assume this question is a subquestion of a bigger exercise.
I believe we might be able to answer your question more accurately if you post the rest of the questions along with this question.
Even though you might already know the answer to those it could help us understand your question.
 Feb 5, 2014
 #3
avatar+135 
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AngelIshtar7:

Ranges from 6.57 to 7.93. Write the desired point ± tolerance statement. How do I do this?



Hi AngelIshtar7!

As Melody said, the logical interpretation is that you need 7.25±0.68.

That is, unless those bounds are absolute upper and lower bounds, meaning it is 100% certain the measurement is in that range.
(I'm stretching here, so please clarify.)
A tolerance is intended to catch 67% of the cases.
In that case we need to make an assumption about the probability distribution.
For instance, assuming a uniform distribution, the tolerance statement would be 7.25±0.46.
 Feb 5, 2014
 #4
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Oh thank you everyone! I finally got the answer I was racking my brain all day ahaha
 Feb 5, 2014

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