The length of a rectangle is 4 ft more than twice the width. The area of the rectangle is 48 ft2. Find the dimensions of the rectangle.
+129840 Let the width = w
Let the length = 2w + 4
So.....
l * w = 48
Substituting, we have
(2w + 4) (w) = 48 simplify
2w^2 + 4w = 48 subtract 48 from both sides
2w^2 + 4w - 48 = 0 divide through by 2
w^2 + 2w - 24 = 0 factor
(w + 6) (w - 4) = 0 set both factors to 0 and w = -6 feet [ not possible ] or w = 4ft
And the length, l, = 2w + 4 = 2(4) + 4 = 8 + 4 = 12 ft
